Șepreuș

Șepreuș
Șepreuș
Commune
	Șepreuș Location in Romania
	Coordinates: 46°34′N 21°44′E / 46.567°N 21.733°E
Country	Romania
County	Arad
Population (2021-12-01)	2,752
Time zone	EET/EEST (UTC+2/+3)
Vehicle reg.	AR

Șepreuș (Hungarian: Seprős) is a commune in Arad County, Romania, is situated on the northern part of the Teuz Plateau, it stretches over 5768 ha. It is composed of a single village, Șepreuș, situated at 63 km from Arad.

Population

According to the last census, the population of the commune counts 2472 inhabitants, out of which 89.6% are Romanians, 0.8% Hungarians, 9.3% Roma and 0.3% are of other or undeclared nationalities.

History

The first documentary record of the locality Șepreuș dates back to 1407.

Economy

The economy of the commune is based on agriculture, mainly on growing of grain, maize, sunflower, barley, sugar-beet, vegetable, oil plants, fodder-crop and technical crops.

Tourism

Șepreuș is known for its fishponds and its castle built in the 19th century.

References

^ "Populaţia rezidentă după grupa de vârstă, pe județe și municipii, orașe, comune, la 1 decembrie 2021" (XLS). National Institute of Statistics.

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[1] "Populaţia rezidentă după grupa de vârstă, pe județe și municipii, orașe, comune, la 1 decembrie 2021" (XLS). National Institute of Statistics.

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Șepreuș
Commune
Șepreuș Location in Romania
Coordinates: 46°34′N 21°44′E / 46.567°N 21.733°E / 46.567; 21.733
Country	Romania
County	Arad
Population (2021-12-01)^[1]	2,752
Time zone	EET/EEST (UTC+2/+3)
Vehicle reg.	AR