Packwood House-American Hotel
(Redirected from 10 Market Street (Lewisburg, Pennsylvania))
The Packwood House-American Hotel, also known as the Packwood House Museum, is historic inn and tavern that is located in Lewisburg, Union County, Pennsylvania, United States.
Packwood House-American Hotel | |
Location | 10 Market Street, Lewisburg, Pennsylvania |
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Coordinates | 40°57′59″N 76°52′57″W / 40.96639°N 76.88250°W |
Area | 0.5 acres (0.20 ha) |
Built | c. 1813, c. 1866 |
NRHP reference No. | 78002475[1] |
Added to NRHP | September 20, 1978 |
Located on Market Street in the Lewisburg Historic District, it was listed on the National Register of Historic Places in 1978.[1]
History and architectural features
editBuilt circa 1813 and expanded circa 1866, this historic structure is a three-story, log and frame building with a gable roof. It has a two-story, pent roof, rear addition. It has housed a decorative arts museum since 1972.[2]
It was listed on the National Register of Historic Places in 1978. It is located in the Lewisburg Historic District.[1]
References
edit- ^ a b c "National Register Information System". National Register of Historic Places. National Park Service. July 9, 2010.
- ^ "National Historic Landmarks & National Register of Historic Places in Pennsylvania" (Searchable database). CRGIS: Cultural Resources Geographic Information System. Note: This includes Charles M. Snyder and Susan M. Zacher (December 1977). "National Register of Historic Places Inventory Nomination Form: Packwood House-American Hotel" (PDF). Retrieved June 3, 2012.