1955 Wimbledon Championships – Girls' singles
(Redirected from 1955 Wimbledon Championships – Girls' Singles)
Sheila Armstrong defeated Béatrice de Chambure in the final, 6–2, 6–4 to win the girls' singles tennis title at the 1955 Wimbledon Championships.[1]
Girls' singles | |
---|---|
1955 Wimbledon Championships | |
Champion | Sheila Armstrong |
Runner-up | Béatrice de Chambure |
Score | 6–2, 6–4 |
Draw | 12 |
Draw
editKey
edit- Q = Qualifier
- WC = Wild card
- LL = Lucky loser
- Alt = Alternate
- SE = Special exempt
- PR = Protected ranking
- ITF = ITF entry
- JE = Junior exempt
- w/o = Walkover
- r = Retired
- d = Defaulted
- SR = Special ranking
Draw
editFirst round | Quarterfinals | Semifinals | Final | ||||||||||||||||||||||||
T Dahl | 0 | 3 | |||||||||||||||||||||||||
W Middleton | 6 | 6 | |||||||||||||||||||||||||
W Middleton | 4 | 4 | |||||||||||||||||||||||||
Béatrice de Chambure | 6 | 6 | Béatrice de Chambure | 6 | 6 | ||||||||||||||||||||||
Gene Hogan | 0 | 0 | Béatrice de Chambure | 6 | 6 | ||||||||||||||||||||||
G Stelges | 4 | 10 | 3 | Fredy Marinkelle | 0 | 1 | |||||||||||||||||||||
Fredy Marinkelle | 6 | 8 | 6 | Béatrice de Chambure | 2 | 4 | |||||||||||||||||||||
Sheila Armstrong | 6 | 6 | Sheila Armstrong | 6 | 6 | ||||||||||||||||||||||
B Lorentzen | 0 | 1 | Sheila Armstrong | 6 | 7 | ||||||||||||||||||||||
D Crampton | 7 | 2 | MN Fossion | 1 | 5 | ||||||||||||||||||||||
MN Fossion | 9 | 6 | Sheila Armstrong | 6 | 6 | ||||||||||||||||||||||
Valerie Koortzen | 3 | 2 | |||||||||||||||||||||||||
Valerie Koortzen | 6 | 6 | |||||||||||||||||||||||||
L Engdahl | 0 | 2 |
References
edit- ^ "Girls' Singles Finals 1947-2017". wimbledon.com. Wimbledon Championships. Retrieved 13 August 2017.
External links
edit- Source for the draw at Wimbledon.com