1974 Wimbledon Championships – Girls' singles

Mima Jaušovec defeated Mariana Simionescu in the final, 7–5, 6–4 to win the girls' singles tennis title at the 1974 Wimbledon Championships.[1]

Girls' singles
1974 Wimbledon Championships
Final
ChampionSocialist Federal Republic of Yugoslavia Mima Jaušovec
Runner-upRomania Mariana Simionescu
Score7–5, 6–4
Details
Draw25
Events
Singles men women boys girls
Doubles men women mixed boys girls
← 1973 · Wimbledon Championships · 1975 →

Draw

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Finals

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Semifinals Final
          
  Chris O'Neil 4 3
  Mariana Simionescu 6 6
  Mariana Simionescu 5 4
  Mima Jaušovec 7 6
  Sue Barker 4 4
  Mima Jaušovec 6 6

Top half

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First round Second round Quarterfinals Semifinals
  E Celigoj 0 4
  Regina Maršíková 6 6
  R Maršíková 6 4
  C O'Neil 8 6
  Chris O'Neil 6 6
  R Heller 1 4   A Rüegg 2 0
  Annemarie Rüegg 6 6   C O'Neil 4 3
  Bernadette Davy 0 4   M Simionescu 6 6
  Kathy May 6 6   K May 4 7 4
  María Mateo 3 4   M Simionescu 6 5 6
  Mariana Simionescu 6 6   M Simionescu 3 6 6
  Linky Boshoff w/o   I Pohmann 6 1 4
  A Gerain   A Gerain 4 2
  Léa Rios de Almeida 4 6 4   I Pohmann 6 6
  Inge Pohmann 6 3 6

Bottom half

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First round Second round Quarterfinals Semifinals
  Sue Barker 6 6
  Adriana Villagrán 2 2   S Barker 6 6
  Jeannine Balbiers 9 3 6   J Balbiers 1 1
  E Torkildsen 7 6 3   S Barker 6 6
  Helena Anliot 6 6   H Anliot 4 1
  Elina Durchman 1 0   H Anliot 6 6
  DA Mushlian 6 3 2   B Sluyter 0 4
  B Sluyter 4 6 6   S Barker 4 4
  M Jaušovec 6 6
  Mima Jaušovec 6 6
  Hoda Baligh 0 0
  M Jaušovec 6 6
  H Sparre 3 4
  Christine Gimmig 3 3
  Helle Sparre 6 6

References

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  1. ^ "Girls' Singles Finals 1947-2017". wimbledon.com. Wimbledon Championships. Retrieved 13 August 2017.
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