1988 Arab Cup final

(Redirected from 1988 Arab Cup Final)

The 1988 Arab Cup Final was a football match that took place on 21 July 1988, at the Amman International Stadium in Amman, Jordan, to determine the winner of the 1988 Arab Cup. Iraq defeated Syria 4–3 on penalties after a draw 1–1 to win their fourth Arab Cup.[1]

1988 Arab Cup Final
Event1988 Arab Cup
Iraq won 4–3 on penalties
Date21 July 1988
VenueAmman International Stadium, Amman
RefereeAbdelali Naciri (Morocco)
Attendance15 000
1985
1992

Road to the final

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Iraq Syria
Opponents Results Opponents Results
Group stage
  Tunisia 1–1   Algeria UT 1–1
  Lebanon 0–0   Bahrain 2–1
  Saudi Arabia Ol. 2–0   Kuwait Ol. 1–0
  Egypt 0–0   Jordan 0–2
Semi-finals
  Jordan 3–0   Egypt 0–0 (4–3 p)

Match

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Details

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Iraq  1–1 (a.e.t.)  Syria
  • Gorgis   34'
Penalties
4–3
Attendance: 15 000
Referee: Abdelali Naciri (Morocco)
 
 
 
 
 
 
 
 
 
 
Iraq
 
 
 
 
 
 
 
 
 
Syria
Iraq:
GK 1 Ahmad Jassim
DF 3 Hassan Kamal
DF 4 Ghanim Oraibi
DF 5 Samir Shaker (c)
DF 13 Karim Allawi
MF 6 Habib Jafar
MF 9 Ismail Mohammed
MF 14 Basil Gorgis
FW 8 Ahmed Radhi
FW 11 Saad Qais
FW 15 Younis Abed Ali
Substitutes:
GK 22 Omar Ahmed Tawfiq
DF 12 Mudhafar Jabbar
DF 18 Karim Salman
MF 2 Salam Hashim
MF 7 Naeem Saddam
MF 10 Rahim Hameed
MF 17 Laith Hussein  
Manager:
Ammo Baba
Syria:
GK 22 Malek Shakuhi
DF 3 Ammar Habib
DF 4 Yousef Hawla
DF 12 Ahmad Al-Shaar
DF 17 Samer Darwish
MF 6 Saad Saad
MF 8 Abdul Kader Kardaghli (c)
MF 14 Mohammad Jakalan
FW 9 Nizar Mahrous
FW 11 Hussein Deeb
FW 18 Walid Al-Nasser
Substitutes:
GK 21 Walid Islam
DF 13 Abdullah Saddikah
DF 19 Joseph Leyous  
MF 10 Faisal Ahmad  
MF 25 Radwan Ajam
Manager:
  Anatoliy Azarenkov

Assistant referees:
... ... (...)
... ... (...)
Fourth official:
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Man of the Match:
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References

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  1. ^ "كأس العرب الخامسة في السعودية 1988 النهائي". kooora.com.
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