Ceru-Băcăinți

(Redirected from Ceru Băcăinţi)

Ceru-Băcăinți (German: Bocksdorf; Hungarian: Bokajfelfalu) is a commune located in Alba County, Transylvania, Romania. It has a population of 227 as of 2021 and is composed of ten villages: Bolovănești, Bulbuc (Bulbuk), Ceru-Băcăinți, Cucuta, Curpeni (Kurpény), Dumbrăvița, Fântânele, Groși, Valea Mare (Váleamáre), and Viezuri (Gyézuri házcsoport).

Ceru-Băcăinți
Location in Alba County
Location in Alba County
Ceru-Băcăinți is located in Romania
Ceru-Băcăinți
Ceru-Băcăinți
Location in Romania
Coordinates: 45°59′N 23°15′E / 45.983°N 23.250°E / 45.983; 23.250
CountryRomania
CountyAlba
Government
 • Mayor (2020–2024) Ioan Trif (PMP)
Area
49.5 km2 (19.1 sq mi)
Elevation
405 m (1,329 ft)
Population
 (2021-12-01)[1]
227
 • Density4.6/km2 (12/sq mi)
Time zoneEET/EEST (UTC+2/+3)
Postal code
RO–517220
Area code(+40) 02 58
Vehicle reg.AB
Websitecerubacainti.ro

The commune is situated in the western part of the county, on the border with Hunedoara County. It lies in the southwestern part of the Metaliferi Mountains; with an altitude of 860 m (2,820 ft), the Piatra Tomii peak dominates Bulbuc village.[2]

Historical population
YearPop.±%
1850 1,339—    
1900 1,916+43.1%
1977 831−56.6%
2002 376−54.8%
2011 269−28.5%
2021 227−15.6%
Source: INS, Census data

References

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  1. ^ "Populaţia rezidentă după grupa de vârstă, pe județe și municipii, orașe, comune, la 1 decembrie 2021" (XLS). National Institute of Statistics.
  2. ^ "Cadrul Natural". cerubacainti.ro (in Romanian). Ceru-Băcăinți townhall. Retrieved July 21, 2021.