1967–68 Coupe de France

(Redirected from Coupe de France 1967-68)

The Coupe de France's results of the 1967–68 season. AS Saint-Étienne won the final played on May 12, 1968, beating Girondins de Bordeaux.

1967–68 Coupe de France
Tournament details
Country France

Round of 16

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Team 1  Score  Team 2
AS Saint-Étienne (D1) 2–1 Angers SCO (D1)
FC Metz (D1) 2–1 AS Nancy (D2)
AS Angoulême (D2) 2–0 FC Rouen (D1)
FC Sochaux-Montbéliard (D1) 2–1 FC Nantes (D1)
Girondins de Bordeaux (D1) 2–0 Gazélec Ajaccio (CFA)
RC Strasbourg (D1) 0–0 (a.e.t.) Red Star (D1)
US Quevilly (CFA) 1–0 Olympique Lyonnais (D1)
USL Dunkerque (D2) 1–0 OGC Nice (D1)
Replay
RC Strasbourg (D1) 1–0 Red Star (D1)

Quarter-finals

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Team 1  Score  Team 2
AS Saint-Étienne (D1) 1–0 FC Metz (D1)
AS Angoulême (D2) 2–1 (a.e.t.) FC Sochaux-Montbéliard (D1)
Girondins de Bordeaux (D1) 1–1 (a.e.t.) RC Strasbourg (D1)
US Quevilly (CFA) 4–0 USL Dunkerque (D2)
Replay
Girondins de Bordeaux (D1) 2–1 RC Strasbourg (D1)

Semi-finals

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AS Saint-Étienne (1)1–1 (a.e.t.)AS Angoulême (2)
Mekhloufi   29' (Report) Grizzetti   33'

Girondins de Bordeaux (1)2–1 (a.e.t.)US Quevilly (3)
Massé   34'
Duhayot   99'
(Report) Leroy   13'

Replay

AS Saint-Étienne (1)2–1AS Angoulême (2)
Herbin   26'
Revelli   70'
(Report) Grizzetti   83'

Final

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Saint-Étienne2–1Bordeaux
Mekloufi   30', 78' Report Wojciak   5'

References

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