1906 Croatian parliamentary election
(Redirected from Croatian parliamentary election, 1906)
Parliamentary elections were held in the Kingdom of Croatia-Slavonia on 3, 4 and 5 May 1906. 45,381 people were entitled to vote in the elections. The People's Party won 37 seats, the Croat-Serb Coalition 32 seats, and Starčević's Party of Rights (led by Josip Frank) won 19.[1] On 30 April Nikola Tomašić, leader of the People's Party, renounced his candidature and left politics for a short time.[2]
![]() | |||||||||||||||||||||||||
| |||||||||||||||||||||||||
88 seats in the Sabor | |||||||||||||||||||||||||
---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|---|
Turnout | 73.35% | ||||||||||||||||||||||||
| |||||||||||||||||||||||||
![]() Results of the election in each of the electoral districts in 8 counties of the Kingdom of Croatia-Slavonia: the party with the plurality of votes in each district. People's Party Starčević's Party of Rights Party of Rights Serb Independent Party Croatian People's Progressive Party Serb People's Radical Party Independent |
![](http://upload.wikimedia.org/wikipedia/commons/thumb/0/0d/Croatian_Parliamentary_Election_Results_1906.png/220px-Croatian_Parliamentary_Election_Results_1906.png)
Results
editParty or alliance | Votes | % | Seats | |||
---|---|---|---|---|---|---|
People's Party | 37 | |||||
Croat-Serb Coalition | Party of Rights | 16 | ||||
Serb Independent Party | 6 | |||||
Croatian People's Progressive Party | 2 | |||||
Serb People's Radical Party | 2 | |||||
Independents | 6 | |||||
Starčević's Party of Rights | 19 | |||||
Total | 88 | |||||
Total votes | 33,289 | – | ||||
Registered voters/turnout | 45,381 | 73.35 |
References
edit- ^ Stjepan Matković: Čista stranka prava i stranački izbori na prijelazu 19. u 20. stoljeće, Hrvatski institut za povijest, Zagreb, p. 89-90
- ^ Zavičaj, 1906 : broj 12 4.4.1906., stranica 2