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Summary
| Description |
English: With the cost assignment of 1 to D, 2 to T and 1 to L, the pattern presented has two possible most parsimonious solutions, using a transfer or a duplication and a loss, both with cost 2. So if we have a tree where the pattern appear multiple times the number of possible most parsimonious solutions tends to be exponential. |
| Date | |
| Source | Own work |
| Author | Hugo Menet |
Licensing
I, the copyright holder of this work, hereby publish it under the following license:
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| Date/Time | Thumbnail | Dimensions | User | Comment | |
|---|---|---|---|---|---|
| current | 13:11, 29 March 2022 | | 242 × 151 (35 KB) | Hmenet | Uploaded own work with UploadWizard |
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