Suplacu de Barcău

(Redirected from Foglaș)

Suplacu de Barcău (Hungarian: Berettyószéplak, Slovak: Siplak) is a commune in Bihor County, Crișana, Romania with a population of 3,813 as of 2021. It is composed of six villages: Borumlaca (Baromlak), Dolea (Dólyapuszta), Foglaș (Fogás; Fogaš), Suplacu de Barcău, Valea Cerului (Cserpatak), and Vâlcelele (Blágarét).

Suplacu de Barcău
Berettyószéplak
Wooden church in Borumlaca
Wooden church in Borumlaca
Location in Bihor County
Location in Bihor County
Suplacu de Barcău is located in Romania
Suplacu de Barcău
Suplacu de Barcău
Location in Romania
Coordinates: 47°15′N 22°32′E / 47.250°N 22.533°E / 47.250; 22.533
CountryRomania
CountyBihor
Government
 • Mayor (2020–2024) Nicolae Tivadar (PNL)
Area
44.48 km2 (17.17 sq mi)
Elevation
169 m (554 ft)
Population
 (2021-12-01)[1]
3,813
 • Density86/km2 (220/sq mi)
Time zoneEET/EEST (UTC+2/+3)
Postal code
417535
Area code+(40) 259
Vehicle reg.BH
Websitewww.suplacudebarcau.ro

History

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The two oldest villages in the commune, Suplacu de Barcău and Borumlaca, were partly depopulated between 1686 and 1692, as a result of the Great Turkish War; the previous inhabitants began to return once hostilities ceased.[2] Numerous families of Slovak colonists arrived in the late 18th century, leading to the appearance of two other villages, Vâlcelele and Valea Cerului. The final two, Dolea and Foglaș, date to 1905 and 1916, respectively.[3]

Natives

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See also

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Notes

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  1. ^ "Populaţia rezidentă după grupa de vârstă, pe județe și municipii, orașe, comune, la 1 decembrie 2021" (XLS). National Institute of Statistics.
  2. ^ Istoria..., pp. 95-96
  3. ^ Istoria..., p. 99

References

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