Diiodine oxide

(Redirected from Iodine(I) oxide)

Diiodine oxide, also known as iodo hypoiodite, is an oxide of iodine that is equivalent to an acid anhydride of hypoiodous acid. This substance is unstable and it is very difficult to isolate.[2]

Diiodine oxide or Iodo hypoiodite
Names
IUPAC name
Diiodine oxide
Systematic IUPAC name
Iodo hypoiodite[1]
Other names
Iodine hypoiodide, diiodooxidane, diiodine monoxide, hypoiodous anhydride
Identifiers
3D model (JSmol)
  • InChI=1S/I2O/c1-3-2
    Key: VSHDHKDWBUMJIJ-UHFFFAOYSA-N
  • O(I)I
Properties
I2O
Molar mass 269.808 g/mol
Related compounds
Related compounds
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).

Preparation

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Diiodine oxide can be prepared by reacting iodine with potassium iodate (KIO3) in 96% sulfuric acid and then extracting it into chlorinated solvents.[2]

Reactions

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Diiodine oxide reacts with water to form hypoiodous acid:

I2O + H2O → 2 HIO

References

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  1. ^ "Epoxy-iodide".
  2. ^ a b Furrow, Stanley D.; Schmitz, Guy E. (2019-09-01). "I2O in solution and volatility". Chemical Physics Letters. 730: 186–190. Bibcode:2019CPL...730..186F. doi:10.1016/j.cplett.2019.05.052. ISSN 0009-2614. S2CID 191207025.