Johnson Township is one of eleven townships in Ripley County, Indiana. As of the 2020 census, its population was 3,763 (up from 3,685 at 2010[3]) and it contained 1,710 housing units.[4]
Johnson Township | |
|---|---|
 | |
| Coordinates: 39°03′32″N 85°14′59″W / 39.05889°N 85.24972°W | |
| Country | United States |
| State | Indiana |
| County | Ripley |
| Government | |
| • Type | Indiana township |
| Area | |
• Total | 54.98 sq mi (142.4 km2) |
| • Land | 54.62 sq mi (141.5 km2) |
| • Water | 0.35 sq mi (0.9 km2) |
| Elevation | 955 ft (291 m) |
| Population (2020) | |
• Total | 3,763 |
| • Density | 68/sq mi (26/km2) |
| Area code | 812 |
| FIPS code | 18-38754[2] |
| GNIS feature ID | 453516 |
| Census | Pop. | Note | %± |
|---|---|---|---|
| 1890 | 2,041 | — | |
| 1900 | 2,232 | 9.4% | |
| 1910 | 2,066 | −7.4% | |
| 1920 | 1,897 | −8.2% | |
| 1930 | 1,747 | −7.9% | |
| 1940 | 1,875 | 7.3% | |
| 1950 | 2,169 | 15.7% | |
| 1960 | 2,296 | 5.9% | |
| 1970 | 2,266 | −1.3% | |
| 1980 | 2,960 | 30.6% | |
| 1990 | 3,190 | 7.8% | |
| 2000 | 3,399 | 6.6% | |
| 2010 | 3,685 | 8.4% | |
| 2020 | 3,763 | 2.1% | |
| Source: US Decennial Census[5] | |||
Geography
editAccording to the 2010 census, the township has a total area of 54.98 square miles (142.4 km2), of which 54.62 square miles (141.5 km2) (or 99.35%) is land and 0.35 square miles (0.91 km2) (or 0.64%) is water.[3]
Cities and towns
editUnincorporated towns
editReferences
edit- ^ "US Board on Geographic Names". United States Geological Survey. October 25, 2007. Retrieved January 31, 2008.
- ^ "U.S. Census website". United States Census Bureau. Retrieved January 31, 2008.
- ^ a b "Population, Housing Units, Area, and Density: 2010 - County -- County Subdivision and Place -- 2010 Census Summary File 1". United States Census. Archived from the original on February 12, 2020. Retrieved May 10, 2013.
- ^ "Explore Census Data". data.census.gov. Retrieved April 10, 2024.
- ^ "Township Census Counts: STATS Indiana".
External links
edit
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