The Izvorul Alb is a right tributary of the river Moldova in Romania.[1][2][3] It flows into the Moldova in Câmpulung Moldovenesc.[4] Its length is 9 km (5.6 mi) and its basin size is 25 km2 (9.7 sq mi).[2]
| Izvorul Alb | |
|---|---|
  | |
| Location | |
| Country | Romania |
| Counties | Suceava County |
| Physical characteristics | |
| Source | Giumalău Mountains |
| Mouth | Moldova |
• location | Câmpulung Moldovenesc |
• coordinates | 47°31′06″N 25°36′12″E / 47.5183°N 25.6034°E |
| Length | 9 km (5.6 mi) |
| Basin size | 25 km2 (9.7 sq mi) |
| Basin features | |
| Progression | Moldova→ Siret→ Danube→ Black Sea |
| Tributaries | |
| • right | Limpedea |
References
edit- ^ "Planul național de management. Sinteza planurilor de management la nivel de bazine/spații hidrografice, anexa 7.1" (PDF, 5.1 MB). Administrația Națională Apele Române. 2010. p. 933.
- ^ a b Atlasul cadastrului apelor din România. Partea 1 (in Romanian). Bucharest: Ministerul Mediului. 1992. p. 377. OCLC 895459847. River code: XII.1.40.17
- ^ Ovidiu Gabor - "Economic Mechanism in Water Management" (PDF). Archived from the original (PDF) on 5 March 2009. Retrieved 2009-03-05., map page 10
- ^ Izvorul Alb (jud. Suceava), e-calauza.ro
