1988 Minnesota House of Representatives election
(Redirected from Minnesota House of Representatives election, 1988)
The 1988 Minnesota House of Representatives election was held in the U.S. state of Minnesota on November 8, 1988, to elect members to the House of Representatives of the 76th Minnesota Legislature. A primary election was held on September 13, 1988.
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All 134 seats in the Minnesota House of Representatives 68 seats needed for a majority | ||||||||||||||||||||||||||||||||||
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The Minnesota Democratic–Farmer–Labor Party (DFL) won a majority of seats, remaining the majority party, followed by the Independent-Republicans of Minnesota. The new Legislature convened on January 3, 1989.
Results
editParty | Candidates | Votes | Seats | |||
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No. | ∆No. | % | ||||
Minnesota Democratic–Farmer–Labor Party | 130 | 1,059,605 | 81 | 1 | 60.45 | |
Independent-Republicans of Minnesota | 128 | 946,820 | 53 | 1 | 39.55 | |
American Party of Minnesota | N/A | 1,338 | 0 | 0.00 | ||
Independent | N/A | 3,335 | 0 | 0.00 | ||
Total | 134 | ±0 | 100.00 | |||
Turnout (out of 3,087,194 eligible voters)[1] | 2,125,119 | 68.84% | 20.67 pp | |||
Source: Minnesota Secretary of State,[2] Minnesota Legislative Reference Library[3] |
See also
editReferences
edit- ^ "Minnesota election statistics 1950-2014" (PDF). Minnesota Secretary of State. Retrieved August 13, 2016.[permanent dead link ]
- ^ "Minnesota Election Results 1988" (PDF). Minnesota Secretary of State. pp. 24–170. Retrieved November 1, 2015.
- ^ "Party Control of the Minnesota House of Representatives, 1951-present". Minnesota Legislative Reference Library. Retrieved November 26, 2015.