Osmium pentafluoride

(Redirected from Osmium(V) fluoride)

Osmium pentafluoride is an inorganic compound with the formula OsF5. It is a blue-green solid. Like the pentafluorides of Ru, Rh, and Ir, OsF5 exists as a tetramer in the solid state.

Osmium pentafluoride
Identifiers
3D model (JSmol)
  • InChI=1S/5FH.Os/h5*1H;/q;;;;;+5/p-5
    Key: RFWLPKSDISVSGM-UHFFFAOYSA-I
  • monomer: F[Os](F)(F)(F)F
  • tetramer: F[Os-]1(F)(F)(F)[F+][Os-](F)(F)(F)(F)[F+][Os-](F)(F)(F)(F)[F+][Os-](F)(F)(F)(F)[F+]1
Properties
F5Os
Molar mass 285.22 g·mol−1
Appearance blue-green solid
Melting point 70 °C (158 °F; 343 K)
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).

Preparation

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Osmium pentafluoride can be prepared by reduction of osmium hexafluoride with iodine as a solution in iodine pentafluoride:[1]

10 OsF6 + I2 → 10 OsF5 + 2 IF5

References

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  1. ^ Holloway, John H.; Mitchell, S. J. (1971). "Preparation and Crystal Structure of Osmium Pentafluoride". Journal of the Chemical Society: 2789–94. doi:10.1039/J19710002789.