Platinum pentafluoride

(Redirected from Platinum(V) fluoride)

Platinum pentafluoride is the inorganic compound with the empirical formula PtF5. This red volatile solid has rarely been studied but is of interest as one of the few binary fluorides of platinum, i.e., a compound containing only Pt and F. It is hydrolyzed in water.[1]

Platinum pentafluoride
Names
IUPAC name
Platinum(V) fluoride
Other names
Platinum pentafluoride
Identifiers
3D model (JSmol)
  • InChI=1S/5FH.Pt/h5*1H;/q;;;;;+5/p-5
    Key: YKYDLLIWWRPCHN-UHFFFAOYSA-I
  • monomer: F[Pt](F)(F)(F)F
  • tetramer: F[Pt-]1(F)(F)(F)[F+][Pt-](F)(F)(F)(F)[F+][Pt-](F)(F)(F)(F)[F+][Pt-]([F+]1)(F)(F)(F)F
Properties
F5Pt
Molar mass 290.07
Appearance red solid
Melting point 75–76 °C (167–169 °F; 348–349 K)
Boiling point 300–305 °C (572–581 °F; 573–578 K)
Related compounds
Related compounds
Platinum(IV) fluoride
Platinum(VI) fluoride
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).

The compound was first prepared by Neil Bartlett by fluorination of platinum dichloride above 350 °C (below that temperature, only PtF4 forms).[1]

Its structure consists of a tetramer, very similar to that of ruthenium pentafluoride. Within the tetramers, each Pt adopts octahedral molecular geometry, with two bridging fluoride ligands.[2]

References

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  1. ^ a b Bartlett, N.; Lohmann, D. H. (1960). "Two New Fluorides of Platinum". Proceedings of the Chemical Society. London: 14–15. doi:10.1039/PS9600000001.
  2. ^ Mueller, B. G.; Serafin, M. (1992). "Single-crystal investigations on PtF4 and PtF5". European Journal of Solid State Inorganic Chemistry. 29 (4–5): 625–633. doi:10.1002/chin.199245006.[full citation needed]