Zalău (river)

(Redirected from Râpoasa River)

The Zalău (Hungarian: Zilah-patak) is a right tributary of the river Crasna in northwestern Romania.[1][2] It flows through the town Zalău. It discharges into the Crasna in Sărmășag.[3] Its length is 38 km (24 mi) and its basin size is 266 km2 (103 sq mi).[2]

Zalău
Zalău (river) is located in Romania
Zalău (river)
Location
CountryRomania
CountiesSălaj County
VillagesZalău, Hereclean, Badon, Borla, Bocșa, Sălăjeni, Câmpia, Lompirt, Sărmășag
Physical characteristics
MouthCrasna
 • location
Sărmășag
 • coordinates
47°20′26″N 22°48′49″E / 47.3406°N 22.8136°E / 47.3406; 22.8136
Length38 km (24 mi)
Basin size266 km2 (103 sq mi)
Basin features
ProgressionCrasnaTiszaDanubeBlack Sea

Hydronymy

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There are several hypotheses which have been made regarding the origin of the river's name (or of the town with the same name located on the upper reach of the river):

  • the name is derived from the word "silaj", meaning belt in the language spoken by the Eurasian Avars
  • the name is derived from the expression "sil es agz", meaning bed of elm trees in Hungarian
  • the name is a Hungarian transcription of the "Zillenmarkt", the German name of Zalău city.[4]

Tributaries

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The tributaries of the Zalău are:[2]

References

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  1. ^ "Planul național de management. Sinteza planurilor de management la nivel de bazine/spații hidrografice, anexa 7.1" (PDF, 5.1 MB). Administrația Națională Apele Române. 2010. p. 122.
  2. ^ a b c Atlasul cadastrului apelor din România. Partea 1 (in Romanian). Bucharest: Ministerul Mediului. 1992. p. 90. OCLC 895459847. River code: II.2.17
  3. ^ Zalau (jud. Salaj), e-calauza.ro
  4. ^ Municipiul Zalău