Lazu (Mureș)

(Redirected from Rapolţel River)

The Lazu (Hungarian: Láz-patak) is a right tributary of the river Mureș in Transylvania, Romania.[1][2] It discharges into the Mureș in Rapoltu Mare. Its length is 11 km (6.8 mi) and its basin size is 19 km2 (7.3 sq mi).[2] Its name originates from the Hungarian[citation needed], means “Fever Creek”.

Lazu
Láz-patak
Lazu (Mureș) is located in Romania
Lazu (Mureș)
Location
CountryRomania
CountiesHunedoara County
VillagesRapolțel, Rapoltu Mare
Physical characteristics
MouthMureș
 • location
Rapoltu Mare
 • coordinates
45°51′08″N 23°04′53″E / 45.8521°N 23.0815°E / 45.8521; 23.0815
Length11 km (6.8 mi)
Basin size19 km2 (7.3 sq mi)
Basin features
ProgressionMureșTiszaDanubeBlack Sea

References

edit
  1. ^ "Planul național de management. Sinteza planurilor de management la nivel de bazine/spații hidrografice, anexa 7.1" (PDF, 5.1 MB). Administrația Națională Apele Române. 2010. p. 413.
  2. ^ a b Atlasul cadastrului apelor din România. Partea 1 (in Romanian). Bucharest: Ministerul Mediului. 1992. p. 178. OCLC 895459847. River code: IV.1.116c