Ruthenium pentafluoride

(Redirected from Ruthenium(V) fluoride)

Ruthenium pentafluoride is the inorganic compound with the empirical formula RuF5. This green volatile solid has rarely been studied but is of interest as a binary fluoride of ruthenium, i.e. a compound containing only Ru and F. It is sensitive toward hydrolysis. Its structure consists of Ru4F20 tetramers, as seen in the isostructural platinum pentafluoride. Within the tetramers, each Ru adopts octahedral molecular geometry, with two bridging fluoride ligands.[1]

Ruthenium pentafluoride
Names
IUPAC name
ruthenium(V) fluoride
Other names
Ruthenium(V) fluoride, Ruthenium(5+) pentafluoride
Identifiers
3D model (JSmol)
ECHA InfoCard 100.035.015 Edit this at Wikidata
  • InChI=1S/5FH.Ru/h5*1H;/q;;;;;+5/p-5
    Key: IUSPGFXRAJDYRG-UHFFFAOYSA-I
  • monomer: F[Ru](F)(F)(F)F
  • tetramer: F[Ru-]1(F)(F)(F)[F+][Ru-](F)(F)(F)(F)[F+][Ru-](F)(F)(F)(F)[F+][Ru-](F)(F)(F)(F)[F+]1
Properties
F5Ru
Molar mass 196.06 g/mol
Appearance green solid
Density 3.82 g/cm3
Melting point 86.5 °C (187.7 °F; 359.6 K)
Boiling point 227 °C (441 °F; 500 K)
Except where otherwise noted, data are given for materials in their standard state (at 25 °C [77 °F], 100 kPa).

Ruthenium pentafluoride reacts with iodine to give ruthenium(III) fluoride.[2][3]

References

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  1. ^ J. H. Holloway, R. D. Peacock, R. W. H. Small "The crystal structure of ruthenium pentafluoride" J. Chem. Soc., 1964, 644-648. doi:10.1039/JR9640000644
  2. ^ A. F. Holleman (2019), Lehrbuch der anorganischen Chemie (in German), Walter de Gruyter GmbH & Co KG, p. 1418, ISBN 978-3-11-083817-6
  3. ^ E.A. Seddon, K.R. Seddon (2013), The Chemistry of Ruthenium (in German), Elsevier, p. 155, ISBN 978-1-4832-8990-8