Sandin (Russian: Сандин; Bashkir: Санйын, Sanyın) is a rural locality (a khutor) in Yermolayevsky Selsoviet, Kuyurgazinsky District, Bashkortostan, Russia. The population was 13 as of 2010.[2] There is 1 street.
Sandin
Сандин | |
|---|---|
Khutor | |
  Sandin  Sandin | |
| Coordinates: 52°37′N 55°37′E / 52.617°N 55.617°E[1] | |
| Country | Russia |
| Region | Bashkortostan |
| District | Kuyurgazinsky District |
| Time zone | UTC+5:00 |
Geography
editSandin is located 18 km southwest of Yermolayevo (the district's administrative centre) by road. Sandin 2-y is the nearest rural locality.[3]
References
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