The Leșunțul Mare is a right tributary of the river Oituz in Romania.[1][2] It discharges into the Oituz in Ferestrău-Oituz. Its length is 11 km (6.8 mi) and its basin size is 48 km2 (19 sq mi).[1]
| Leșunțul Mare | |
|---|---|
  | |
| Location | |
| Country | Romania |
| Counties | Bacău County |
| Physical characteristics | |
| Mouth | Oituz |
• coordinates | 46°12′02″N 26°34′35″E / 46.2005°N 26.5765°E |
| Length | 11 km (6.8 mi) |
| Basin size | 48 km2 (19 sq mi) |
| Basin features | |
| Progression | Oituz→ Trotuș→ Siret→ Danube→ Black Sea |
| Tributaries | |
| • left | Leșunțul Mic |
References
edit- ^ a b Atlasul cadastrului apelor din România. Partea 1 (in Romanian). Bucharest: Ministerul Mediului. 1992. p. 407. OCLC 895459847. River code: XII.1.69.31.3
- ^ Ovidiu Gabor - "Economic Mechanism in Water Management" (PDF). Archived from the original (PDF) on 5 March 2009. Retrieved 2009-03-05., map page 10
