1990 State of the Union Address

(Redirected from State of the Union 1990)

The 1990 State of the Union Address was given by the 41st president of the United States, George H. W. Bush, on January 31, 1990, at 9:00 p.m. EST, in the chamber of the United States House of Representatives to the 101st United States Congress. It was Bush's first State of the Union Address and his second speech to a joint session of the United States Congress. Presiding over this joint session was the House speaker, Tom Foley, accompanied by Dan Quayle, the vice president, in his capacity as the president of the Senate.

1990 State of the Union Address
President George H. W. Bush delivering the address. Sitting behind Bush are Vice President Dan Quayle and House Speaker Tom Foley.
DateJanuary 31, 1990 (1990-01-31)
Time9:00 p.m. EST
Duration35 minutes
VenueHouse Chamber, United States Capitol
LocationWashington, D.C.
Coordinates38°53′23″N 77°00′32″W / 38.88972°N 77.00889°W / 38.88972; -77.00889
TypeState of the Union Address
Participants
Previous1989 Joint session speech
Next1991 State of the Union Address

The speech lasted 35 minutes and 43 seconds.[1] and contained 3777 words.[2]

The Democratic Party response was delivered by House Speaker Tom Foley (WA).[3]

Edward J. Derwinski, the Secretary of Veterans Affairs, served as the designated survivor.[4]

See also

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References

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  1. ^ "Length of State of the Union Addresses in Minutes". Presidency.ucsb.edu. Retrieved September 27, 2012.
  2. ^ "Length of State of the Union Addresses". Presidency.ucsb.edu. Retrieved September 27, 2012.
  3. ^ "List of Opposition Responses to State of the Union Addresses". Presidency.ucsb.edu. Retrieved September 27, 2012.
  4. ^ "Cabinet Members Who Did Not Attend the State of the Union Address". Presidency.ucsb.edu. Retrieved September 27, 2012.
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Preceded by State of the Union addresses
1990
Succeeded by