Limits for general functions
edit
lim
x
→
c
f
(
x
)
=
L
{\displaystyle \lim _{x\to c}f(x)=L}
if and only if
∀
ε
>
0
∃
δ
>
0
:
0
<
|
x
−
c
|
<
δ
⟹
|
f
(
x
)
−
L
|
<
ε
{\displaystyle \forall \varepsilon >0\ \exists \delta >0:0<|x-c|<\delta \implies |f(x)-L|<\varepsilon }
. This is the (ε, δ)-definition of limit .
The limit superior and limit inferior of a sequence are defined as
lim sup
n
→
∞
x
n
=
lim
n
→
∞
(
sup
m
≥
n
x
m
)
{\displaystyle \limsup _{n\to \infty }x_{n}=\lim _{n\to \infty }\left(\sup _{m\geq n}x_{m}\right)}
and
lim inf
n
→
∞
x
n
=
lim
n
→
∞
(
inf
m
≥
n
x
m
)
{\displaystyle \liminf _{n\to \infty }x_{n}=\lim _{n\to \infty }\left(\inf _{m\geq n}x_{m}\right)}
.
A function,
f
(
x
)
{\displaystyle f(x)}
, is said to be continuous at a point, c , if
lim
x
→
c
f
(
x
)
=
f
(
c
)
.
{\displaystyle \lim _{x\to c}f(x)=f(c).}
Operations on a single known limit
edit
If
lim
x
→
c
f
(
x
)
=
L
{\displaystyle \lim _{x\to c}f(x)=L}
then:
lim
x
→
c
[
f
(
x
)
±
a
]
=
L
±
a
{\displaystyle \lim _{x\to c}\,[f(x)\pm a]=L\pm a}
lim
x
→
c
a
f
(
x
)
=
a
L
{\displaystyle \lim _{x\to c}\,af(x)=aL}
[ 1] [ 2] [ 3]
lim
x
→
c
1
f
(
x
)
=
1
L
{\displaystyle \lim _{x\to c}{\frac {1}{f(x)}}={\frac {1}{L}}}
[ 4] if L is not equal to 0.
lim
x
→
c
f
(
x
)
n
=
L
n
{\displaystyle \lim _{x\to c}\,f(x)^{n}=L^{n}}
if n is a positive integer[ 1] [ 2] [ 3]
lim
x
→
c
f
(
x
)
1
n
=
L
1
n
{\displaystyle \lim _{x\to c}\,f(x)^{1 \over n}=L^{1 \over n}}
if n is a positive integer, and if n is even, then L > 0.[ 1] [ 3]
In general, if g (x ) is continuous at L and
lim
x
→
c
f
(
x
)
=
L
{\displaystyle \lim _{x\to c}f(x)=L}
then
lim
x
→
c
g
(
f
(
x
)
)
=
g
(
L
)
{\displaystyle \lim _{x\to c}g\left(f(x)\right)=g(L)}
[ 1] [ 2]
Operations on two known limits
edit
If
lim
x
→
c
f
(
x
)
=
L
1
{\displaystyle \lim _{x\to c}f(x)=L_{1}}
and
lim
x
→
c
g
(
x
)
=
L
2
{\displaystyle \lim _{x\to c}g(x)=L_{2}}
then:
lim
x
→
c
[
f
(
x
)
±
g
(
x
)
]
=
L
1
±
L
2
{\displaystyle \lim _{x\to c}\,[f(x)\pm g(x)]=L_{1}\pm L_{2}}
[ 1] [ 2] [ 3]
lim
x
→
c
[
f
(
x
)
g
(
x
)
]
=
L
1
⋅
L
2
{\displaystyle \lim _{x\to c}\,[f(x)g(x)]=L_{1}\cdot L_{2}}
[ 1] [ 2] [ 3]
lim
x
→
c
f
(
x
)
g
(
x
)
=
L
1
L
2
if
L
2
≠
0
{\displaystyle \lim _{x\to c}{\frac {f(x)}{g(x)}}={\frac {L_{1}}{L_{2}}}\qquad {\text{ if }}L_{2}\neq 0}
[ 1] [ 2] [ 3]
Limits involving derivatives or infinitesimal changes
edit
In these limits, the infinitesimal change
h
{\displaystyle h}
is often denoted
Δ
x
{\displaystyle \Delta x}
or
δ
x
{\displaystyle \delta x}
. If
f
(
x
)
{\displaystyle f(x)}
is differentiable at
x
{\displaystyle x}
,
lim
h
→
0
f
(
x
+
h
)
−
f
(
x
)
h
=
f
′
(
x
)
{\displaystyle \lim _{h\to 0}{f(x+h)-f(x) \over h}=f'(x)}
. This is the definition of the derivative . All differentiation rules can also be reframed as rules involving limits. For example, if g (x ) is differentiable at x ,
lim
h
→
0
f
∘
g
(
x
+
h
)
−
f
∘
g
(
x
)
h
=
f
′
[
g
(
x
)
]
g
′
(
x
)
{\displaystyle \lim _{h\to 0}{f\circ g(x+h)-f\circ g(x) \over h}=f'[g(x)]g'(x)}
. This is the chain rule .
lim
h
→
0
f
(
x
+
h
)
g
(
x
+
h
)
−
f
(
x
)
g
(
x
)
h
=
f
′
(
x
)
g
(
x
)
+
f
(
x
)
g
′
(
x
)
{\displaystyle \lim _{h\to 0}{f(x+h)g(x+h)-f(x)g(x) \over h}=f'(x)g(x)+f(x)g'(x)}
. This is the product rule .
lim
h
→
0
(
f
(
x
+
h
)
f
(
x
)
)
1
/
h
=
exp
(
f
′
(
x
)
f
(
x
)
)
{\displaystyle \lim _{h\to 0}\left({\frac {f(x+h)}{f(x)}}\right)^{1/h}=\exp \left({\frac {f'(x)}{f(x)}}\right)}
lim
h
→
0
(
f
(
e
h
x
)
f
(
x
)
)
1
/
h
=
exp
(
x
f
′
(
x
)
f
(
x
)
)
{\displaystyle \lim _{h\to 0}{\left({f(e^{h}x) \over {f(x)}}\right)^{1/h}}=\exp \left({\frac {xf'(x)}{f(x)}}\right)}
If
f
(
x
)
{\displaystyle f(x)}
and
g
(
x
)
{\displaystyle g(x)}
are differentiable on an open interval containing c , except possibly c itself, and
lim
x
→
c
f
(
x
)
=
lim
x
→
c
g
(
x
)
=
0
or
±
∞
{\displaystyle \lim _{x\to c}f(x)=\lim _{x\to c}g(x)=0{\text{ or }}\pm \infty }
, L'Hôpital's rule can be used:
lim
x
→
c
f
(
x
)
g
(
x
)
=
lim
x
→
c
f
′
(
x
)
g
′
(
x
)
{\displaystyle \lim _{x\to c}{\frac {f(x)}{g(x)}}=\lim _{x\to c}{\frac {f'(x)}{g'(x)}}}
[ 2]
If
f
(
x
)
≤
g
(
x
)
{\displaystyle f(x)\leq g(x)}
for all x in an interval that contains c , except possibly c itself, and the limit of
f
(
x
)
{\displaystyle f(x)}
and
g
(
x
)
{\displaystyle g(x)}
both exist at c , then[ 5]
lim
x
→
c
f
(
x
)
≤
lim
x
→
c
g
(
x
)
{\displaystyle \lim _{x\to c}f(x)\leq \lim _{x\to c}g(x)}
If
lim
x
→
c
f
(
x
)
=
lim
x
→
c
h
(
x
)
=
L
{\displaystyle \lim _{x\to c}f(x)=\lim _{x\to c}h(x)=L}
and
f
(
x
)
≤
g
(
x
)
≤
h
(
x
)
{\displaystyle f(x)\leq g(x)\leq h(x)}
for all x in an open interval that contains c , except possibly c itself,
lim
x
→
c
g
(
x
)
=
L
.
{\displaystyle \lim _{x\to c}g(x)=L.}
This is known as the squeeze theorem .[ 1] [ 2] This applies even in the cases that f (x ) and g (x ) take on different values at c , or are discontinuous at c .
lim
x
→
c
a
=
a
{\displaystyle \lim _{x\to c}a=a}
[ 1] [ 2] [ 3]
lim
x
→
c
x
=
c
{\displaystyle \lim _{x\to c}x=c}
[ 1] [ 2] [ 3]
lim
x
→
c
(
a
x
+
b
)
=
a
c
+
b
{\displaystyle \lim _{x\to c}(ax+b)=ac+b}
lim
x
→
c
x
n
=
c
n
{\displaystyle \lim _{x\to c}x^{n}=c^{n}}
if n is a positive integer[ 5]
lim
x
→
∞
x
/
a
=
{
∞
,
a
>
0
does not exist
,
a
=
0
−
∞
,
a
<
0
{\displaystyle \lim _{x\to \infty }x/a={\begin{cases}\infty ,&a>0\\{\text{does not exist}},&a=0\\-\infty ,&a<0\end{cases}}}
In general, if
p
(
x
)
{\displaystyle p(x)}
is a polynomial then, by the continuity of polynomials,[ 5]
lim
x
→
c
p
(
x
)
=
p
(
c
)
{\displaystyle \lim _{x\to c}p(x)=p(c)}
This is also true for rational functions , as they are continuous on their domains .[ 5]
lim
x
→
c
x
a
=
c
a
.
{\displaystyle \lim _{x\to c}x^{a}=c^{a}.}
[ 5] In particular,
lim
x
→
∞
x
a
=
{
∞
,
a
>
0
1
,
a
=
0
0
,
a
<
0
{\displaystyle \lim _{x\to \infty }x^{a}={\begin{cases}\infty ,&a>0\\1,&a=0\\0,&a<0\end{cases}}}
lim
x
→
c
x
1
/
a
=
c
1
/
a
{\displaystyle \lim _{x\to c}x^{1/a}=c^{1/a}}
.[ 5] In particular,
lim
x
→
∞
x
1
/
a
=
lim
x
→
∞
x
a
=
∞
for any
a
>
0
{\displaystyle \lim _{x\to \infty }x^{1/a}=\lim _{x\to \infty }{\sqrt[{a}]{x}}=\infty {\text{ for any }}a>0}
[ 6]
lim
x
→
0
+
x
−
n
=
lim
x
→
0
+
1
x
n
=
+
∞
{\displaystyle \lim _{x\to 0^{+}}x^{-n}=\lim _{x\to 0^{+}}{\frac {1}{x^{n}}}=+\infty }
lim
x
→
0
−
x
−
n
=
lim
x
→
0
−
1
x
n
=
{
−
∞
,
if
n
is odd
+
∞
,
if
n
is even
{\displaystyle \lim _{x\to 0^{-}}x^{-n}=\lim _{x\to 0^{-}}{\frac {1}{x^{n}}}={\begin{cases}-\infty ,&{\text{if }}n{\text{ is odd}}\\+\infty ,&{\text{if }}n{\text{ is even}}\end{cases}}}
lim
x
→
∞
a
x
−
1
=
lim
x
→
∞
a
/
x
=
0
for any real
a
{\displaystyle \lim _{x\to \infty }ax^{-1}=\lim _{x\to \infty }a/x=0{\text{ for any real }}a}
Exponential functions
edit
lim
x
→
c
e
x
=
e
c
{\displaystyle \lim _{x\to c}e^{x}=e^{c}}
, due to the continuity of
e
x
{\displaystyle e^{x}}
lim
x
→
∞
a
x
=
{
∞
,
a
>
1
1
,
a
=
1
0
,
0
<
a
<
1
{\displaystyle \lim _{x\to \infty }a^{x}={\begin{cases}\infty ,&a>1\\1,&a=1\\0,&0<a<1\end{cases}}}
lim
x
→
∞
a
−
x
=
{
0
,
a
>
1
1
,
a
=
1
∞
,
0
<
a
<
1
{\displaystyle \lim _{x\to \infty }a^{-x}={\begin{cases}0,&a>1\\1,&a=1\\\infty ,&0<a<1\end{cases}}}
[ 6]
lim
x
→
∞
a
x
=
lim
x
→
∞
a
1
/
x
=
{
1
,
a
>
0
0
,
a
=
0
does not exist
,
a
<
0
{\displaystyle \lim _{x\to \infty }{\sqrt[{x}]{a}}=\lim _{x\to \infty }{a}^{1/x}={\begin{cases}1,&a>0\\0,&a=0\\{\text{does not exist}},&a<0\end{cases}}}
lim
x
→
∞
x
x
=
lim
x
→
∞
x
1
/
x
=
1
{\displaystyle \lim _{x\to \infty }{\sqrt[{x}]{x}}=\lim _{x\to \infty }{x}^{1/x}=1}
lim
x
→
+
∞
(
x
x
+
k
)
x
=
e
−
k
{\displaystyle \lim _{x\to +\infty }\left({\frac {x}{x+k}}\right)^{x}=e^{-k}}
[ 2]
lim
x
→
0
(
1
+
x
)
1
x
=
e
{\displaystyle \lim _{x\to 0}\left(1+x\right)^{\frac {1}{x}}=e}
[ 2]
lim
x
→
0
(
1
+
k
x
)
m
x
=
e
m
k
{\displaystyle \lim _{x\to 0}\left(1+kx\right)^{\frac {m}{x}}=e^{mk}}
lim
x
→
+
∞
(
1
+
1
x
)
x
=
e
{\displaystyle \lim _{x\to +\infty }\left(1+{\frac {1}{x}}\right)^{x}=e}
[ 7]
lim
x
→
+
∞
(
1
−
1
x
)
x
=
1
e
{\displaystyle \lim _{x\to +\infty }\left(1-{\frac {1}{x}}\right)^{x}={\frac {1}{e}}}
lim
x
→
+
∞
(
1
+
k
x
)
m
x
=
e
m
k
{\displaystyle \lim _{x\to +\infty }\left(1+{\frac {k}{x}}\right)^{mx}=e^{mk}}
[ 6]
lim
x
→
0
(
1
+
a
(
e
−
x
−
1
)
)
−
1
x
=
e
a
{\displaystyle \lim _{x\to 0}\left(1+a\left({e^{-x}-1}\right)\right)^{-{\frac {1}{x}}}=e^{a}}
. This limit can be derived from this limit .
Sums, products and composites
edit
lim
x
→
0
x
e
−
x
=
0
{\displaystyle \lim _{x\to 0}xe^{-x}=0}
lim
x
→
∞
x
e
−
x
=
0
{\displaystyle \lim _{x\to \infty }xe^{-x}=0}
lim
x
→
0
(
a
x
−
1
x
)
=
ln
a
,
{\displaystyle \lim _{x\to 0}\left({\frac {a^{x}-1}{x}}\right)=\ln {a},}
for all positive a .[ 4] [ 7]
lim
x
→
0
(
e
x
−
1
x
)
=
1
{\displaystyle \lim _{x\to 0}\left({\frac {e^{x}-1}{x}}\right)=1}
lim
x
→
0
(
e
a
x
−
1
x
)
=
a
{\displaystyle \lim _{x\to 0}\left({\frac {e^{ax}-1}{x}}\right)=a}
Logarithmic functions
edit
Trigonometric functions
edit
If
x
{\displaystyle x}
is expressed in radians:
lim
x
→
a
sin
x
=
sin
a
{\displaystyle \lim _{x\to a}\sin x=\sin a}
lim
x
→
a
cos
x
=
cos
a
{\displaystyle \lim _{x\to a}\cos x=\cos a}
These limits both follow from the continuity of sin and cos.
lim
x
→
0
sin
x
x
=
1
{\displaystyle \lim _{x\to 0}{\frac {\sin x}{x}}=1}
.[ 7] [ 8] Or, in general,
lim
x
→
0
sin
a
x
a
x
=
1
{\displaystyle \lim _{x\to 0}{\frac {\sin ax}{ax}}=1}
, for a not equal to 0.
lim
x
→
0
sin
a
x
x
=
a
{\displaystyle \lim _{x\to 0}{\frac {\sin ax}{x}}=a}
lim
x
→
0
sin
a
x
b
x
=
a
b
{\displaystyle \lim _{x\to 0}{\frac {\sin ax}{bx}}={\frac {a}{b}}}
, for b not equal to 0.
lim
x
→
∞
x
sin
(
1
x
)
=
1
{\displaystyle \lim _{x\to \infty }x\sin \left({\frac {1}{x}}\right)=1}
lim
x
→
0
1
−
cos
x
x
=
lim
x
→
0
cos
x
−
1
x
=
0
{\displaystyle \lim _{x\to 0}{\frac {1-\cos x}{x}}=\lim _{x\to 0}{\frac {\cos x-1}{x}}=0}
[ 4] [ 8] [ 9]
lim
x
→
0
1
−
cos
x
x
2
=
1
2
{\displaystyle \lim _{x\to 0}{\frac {1-\cos x}{x^{2}}}={\frac {1}{2}}}
lim
x
→
n
±
tan
(
π
x
+
π
2
)
=
∓
∞
{\displaystyle \lim _{x\to n^{\pm }}\tan \left(\pi x+{\frac {\pi }{2}}\right)=\mp \infty }
, for integer n .
lim
x
→
0
tan
x
x
=
1
{\displaystyle \lim _{x\to 0}{\frac {\tan x}{x}}=1}
. Or, in general,
lim
x
→
0
tan
a
x
a
x
=
1
{\displaystyle \lim _{x\to 0}{\frac {\tan ax}{ax}}=1}
, for a not equal to 0.
lim
x
→
0
tan
a
x
b
x
=
a
b
{\displaystyle \lim _{x\to 0}{\frac {\tan ax}{bx}}={\frac {a}{b}}}
, for b not equal to 0.
lim
n
→
∞
sin
sin
⋯
sin
(
x
0
)
⏟
n
=
0
{\displaystyle \lim _{n\to \infty }\ \underbrace {\sin \sin \cdots \sin(x_{0})} _{n}=0}
, where x 0 is an arbitrary real number.
lim
n
→
∞
cos
cos
⋯
cos
(
x
0
)
⏟
n
=
d
{\displaystyle \lim _{n\to \infty }\ \underbrace {\cos \cos \cdots \cos(x_{0})} _{n}=d}
, where d is the Dottie number . x 0 can be any arbitrary real number.
Notable special limits
edit
lim
n
→
∞
n
n
!
n
=
e
{\displaystyle \lim _{n\to \infty }{\frac {n}{\sqrt[{n}]{n!}}}=e}
lim
n
→
∞
(
n
!
)
1
/
n
=
∞
{\displaystyle \lim _{n\to \infty }\left(n!\right)^{1/n}=\infty }
. This can be proven by considering the inequality
e
x
≥
x
n
n
!
{\displaystyle e^{x}\geq {\frac {x^{n}}{n!}}}
at
x
=
n
{\displaystyle x=n}
.
lim
n
→
∞
2
n
2
−
2
+
2
+
⋯
+
2
⏟
n
=
π
{\displaystyle \lim _{n\to \infty }\,2^{n}\underbrace {\sqrt {2-{\sqrt {2+{\sqrt {2+\dots +{\sqrt {2}}}}}}}} _{n}=\pi }
. This can be derived from Viète's formula for π .