Table tennis at the 1998 Asian Games
(Redirected from Table tennis at the 1998 Asian Games – Men's doubles)
Table tennis was contested in the 1998 Asian Games held in Bangkok, Thailand from December 8 to December 16, 1998. China maintained its dominance in the event and won total nine medals, with six golds. Kim Taek-soo of South Korea was the only non-Chinese player who won a gold medal, and with his medal South Korea finished second in medal table, with total eight medals. North Korea and Hong Kong both achieved one silver and one bronze, and finished tied at a third spot in a medal table rankings.[1]
| Table tennis at the 1998 Asian Games | |
|---|---|
 | |
| Venue | Thammasat Gymnasium 5 |
| Dates | 8–16 December 1998 |
Medalists
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Medal table
edit| Rank | Nation | Gold | Silver | Bronze | Total |
|---|---|---|---|---|---|
| 1 |  China (CHN) | 6 | 2 | 1 | 9 |
| 2 |  South Korea (KOR) | 1 | 3 | 4 | 8 |
| 3 |  Hong Kong (HKG) | 0 | 1 | 1 | 2 |
 North Korea (PRK) | 0 | 1 | 1 | 2 | |
| 5 |  Chinese Taipei (TPE) | 0 | 0 | 5 | 5 |
| 6 |  Japan (JPN) | 0 | 0 | 2 | 2 |
| Totals (6 entries) | 7 | 7 | 14 | 28 | |
References
edit- ^ "Table tennis – Past Medals". doha-2006.com (2006 Asian Games' official website). Wayback Machine. November 26, 2006. Archived from the original on January 4, 2007. Retrieved June 4, 2011.