Talk:Galois representation

Untitled

What is the G for which we are considering O_L as an O_K[G]-module?

The Galois group of L over K. Charles Matthews 09:40, 27 May 2004 (UTC)

Noether's theorem

"Then Noether's theorem states that tame ramification is necessary and sufficient for O_L to be a projective module over Z[G]. It is certainly therefore necessary for it to be a free module." Not every projective module is free, so these two sentences are confusing when taken together. Not familiar with Noether's theorem so can't correct it. Someone please fix. 74.112.174.192 14:37, 3 April 2007 (UTC)

Tame ramification is necessary to be projective. Free is a stronger condition than projective. So tame ramification is necessary to be free. Charles Matthews 19:39, 3 April 2007 (UTC)

Requested move 21 July 2024

The following is a closed discussion of a requested move. Please do not modify it. Subsequent comments should be made in a new section on the talk page. Editors desiring to contest the closing decision should consider a move review after discussing it on the closer's talk page. No further edits should be made to this discussion.

The result of the move request was: moved. Moved as an uncontested request with minimal participation. If there is any objection within a reasonable time frame, please ask me to reopen the discussion; if I am not available, please ask at the technical requests page. (closed by non-admin page mover) Safari Scribe^{Edits! Talk!} 19:42, 5 August 2024 (UTC)

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Galois module → Galois representation – I think "Galois representation" is more common than "Galois module" even though technically the latter is more general. Taku (talk) 11:26, 21 July 2024 (UTC) — Relisting. – robertsky (talk) 21:15, 29 July 2024 (UTC)

The discussion above is closed. Please do not modify it. Subsequent comments should be made on the appropriate discussion page. No further edits should be made to this discussion.