Talk:Larson–Miller relation

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Latest comment: 10 years ago by 67.87.139.9 in topic Final Form

Final Form

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In the equation shown on this page, it shows the larson-miller parameter to be the activation energy over the gas constant and then has log of the time on the other side. Up until this point natural log was being used, in that case it should be the natural log of time. If you want to stick with log, then the larson-miller parameter should be activation energy over gas constant times the log of e. I'm not going to change it since I'm not sure about it, but when I've come across this relation, thats what its been. Chipotlehero (talk) 21:56, 27 April 2008 (UTC)Reply

  • You were right that there was something off about the formula, so I fixed it (the negative sign in front of the ln(1/t) was incorrect). In my experience the formula is normally presented in final form using log instead of ln, but ln is simply used for the derivation because it is easier to use starting from the Arrhenius type equation. Verkhovensky (talk) 01:25, 28 April 2008 (UTC)Reply

I have merged in a few references from the Larson-Miller Parameter page, and made some comment regarding units. Not sure the units stuff is correct. Also I have recommended the Larson-Miller Parameter page be deleted as it is redundant and seems to be collecting contributions.67.87.139.9 (talk) 04:06, 14 January 2014 (UTC)Reply