1806 United States House of Representatives election in Rhode Island
(Redirected from United States House of Representatives election in Rhode Island, 1806)
Rhode Island elected its members August 26, 1806. Rhode Island law required a majority of votes to win. In this election, only one candidate won a majority on the first ballot, and so a run-off election was required to choose the second seat.
| District | Incumbent | Party | First elected |
Result | Candidates[a] |
|---|---|---|---|---|---|
| Rhode Island at-large 2 seats on a general ticket |
Nehemiah Knight | Democratic-Republican | 1802 | Incumbent re-elected. | First ballot: √ Nehemiah Knight (Democratic-Republican) 26.9% Isaac Wilbour (Democratic-Republican) 24.4% William Hunter (Federalist) 22.2% Thomas Arnold (Federalist) 21.8% Thomas B. Hazard (Quid) 4.7% Second ballot: √ Isaac Wilbour (Democratic-Republican) 58.2% William Hunter (Federalist) 41.3% |
| Joseph Stanton Jr. | Democratic-Republican | 1800 | Incumbent retired. New member elected. Democratic-Republican hold. |
See also
editNotes
edit- ^ Only candidates with at least 1% of the vote are listed.
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