1892 United States House of Representatives election in Wyoming
(Redirected from United States House of Representatives election in Wyoming, 1892)
The Wyoming United States House election for 1892 was held on November 3, 1892. Democratic Henry A. Coffeen defeated Republican incumbent Clarence D. Clark with 51.34% of the vote making Clark the first incumbent Representative from Wyoming to lose reelection.
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![]() County results Coffeen: 50–60% 60–70% Clark: 50–60% No Data | |||||||||||||||||
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Results
editParty | Candidate | Votes | % | |
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Democratic | Henry A. Coffeen | 8,855 | 51.34% | |
Republican | Clarence D. Clark (inc.) | 8,394 | 48.66% | |
Total votes | 17,249 | 100% |
References
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