1998 United States House of Representatives election in Wyoming
(Redirected from United States House of Representatives election in Wyoming, 1998)
The 1998 United States House of Representatives election in Wyoming were held on November 3, 1998 to determine who will represent the state of Wyoming in the United States House of Representatives. Wyoming has one, at large district in the House, apportioned according to the 1990 United States census, due to its low population. Representatives are elected for two-year terms.
Major candidates
editDemocratic
edit- Scott Farris
Republican
edit- Barbara Cubin, incumbent U.S. Congresswoman
Results
editParty | Candidate | Votes | % | |
---|---|---|---|---|
Republican | Barbara Cubin (inc.) | 100,687 | 57.79 | |
Democratic | Scott Farris | 67,399 | 38.69 | |
Libertarian | Steve Richardson | 6,133 | 3.52 | |
Total votes | 174,219 | 100.00 | ||
Republican hold |
References
editPreceded by 1996 elections |
United States House elections in Wyoming 1998 |
Succeeded by 2000 elections |