1801 United States Senate election in Pennsylvania
(Redirected from United States Senate election in Pennsylvania, 1801)
The 1801 United States Senate election in Pennsylvania was held on February 19, 1801. Peter Muhlenberg was elected by the Pennsylvania General Assembly to the United States Senate.[1]
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102 Members of the Pennsylvania legislature Plurality of votes needed to win | |||||||||||||||||
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Results
editIncumbent Federalist William Bingham, who was elected in 1795, was not a candidate for re-election to another term. The Pennsylvania General Assembly, consisting of the House of Representatives and the Senate, convened on February 19, 1801, to elect a new Senator to fill the term beginning on March 4, 1801. Two ballots were recorded. The results of the second and final ballot of both houses combined are as follows:
Party | Candidate | Votes | % | |
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Democratic-Republican | Peter Muhlenberg | 46 | 45.10 | |
Democratic-Republican | George Logan | 45 | 44.12 | |
Not voting | 11 | 10.78 | ||
Total votes | 102 | 100 |
References
edit- ^ a b "U.S. Senate Election - 19 February 1801" (PDF). Wilkes University. Retrieved September 28, 2013.