1836 United States Senate election in Pennsylvania
(Redirected from United States Senate election in Pennsylvania, 1836)
The 1836 United States Senate election in Pennsylvania was held on December 14, 1836. Future President of the United States James Buchanan was re-elected by the Pennsylvania General Assembly to the United States Senate.[1]
Background
editAfter Sen. William Wilkins resigned from office to become U.S. Minister to Russia, James Buchanan was elected by the General Assembly, consisting of the House of Representatives and the Senate, in 1834 to serve the remainder of the unexpired term, which was to expire on March 4, 1837.
Results
editThe Pennsylvania General Assembly convened on December 14, 1836, to elect a Senator to serve the term beginning on March 4, 1837. The results of the vote of both houses combined are as follows:
Party | Candidate | Votes | % | |
---|---|---|---|---|
Democratic | James Buchanan (Inc.) | 85 | 63.91 | |
Whig | Thomas M. T. McKennan | 24 | 18.05 | |
Whig | Charles B. Penrose | 21 | 15.79 | |
Democratic | Thomas Cunningham | 1 | 0.75 | |
Democratic | Isaac Leet | 1 | 0.75 | |
N/A | Not voting | 1 | 0.75 | |
Totals | 133 | 100.00% |
References
edit- ^ a b "U.S. Senate Election - 14 December 1836" (PDF). Wilkes University. Retrieved December 22, 2013.