1788–89 United States presidential election in Delaware

Main article: 1788–89 United States presidential election

The 1788–89 United States presidential election in Delaware took place on January 7, 1789, as part of the 1788–1789 United States presidential election to elect the first President. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.

1788–1789 United States presidential election in Delaware

January 7, 1789

Nominee George Washington John Jay Party Independent Independent Home state Virginia New York Electoral vote 3 3

President before election Office established Elected President George Washington Independent

George Mitchell, John Baning, and Gunning Bedford Jr. served as electors. George Washington and John Jay both received three electoral votes.

Results

1788–89 United States presidential election in Delaware

Party		Candidate	Votes	%	±%
	Federalist	George Mitchell	522
	Federalist	Gunning Bedford Jr.	163
	Federalist	John Banning
Total votes			>685	100.00%

See also

• United States presidential elections in Delaware

Works cited

• Jensen, Merrill; Becker, Robert, eds. (1976). The First Federal Elections 1788-1790: Congress, South Carolina, Pennsylvania, Massachusetts, New Hampshire. Vol. 1. University of Wisconsin Press. ISBN 0299066908.