1852 United States presidential election in Delaware
(Redirected from United States presidential election in Delaware, 1852)
The 1852 United States presidential election in Delaware took place on November 2, 1852, as part of the 1852 United States presidential election. Voters chose three representatives, or electors to the Electoral College, who voted for President and Vice President.
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County Results
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Delaware voted for the Democratic candidate, Franklin Pierce, over Whig candidate Winfield Scott. The first Democrat to win Delaware in a presidential election, Pierce carried the state by a very narrow margin of 0.19%, only 25 votes.
Results
edit1852 United States presidential election in Delaware[1] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Democratic | Franklin Pierce of New Hampshire | William Rufus DeVane King of Alabama | 6,318 | 49.85% | 3 | 100.00% | ||
Whig | Winfield Scott of New Jersey | William Alexander Graham of North Carolina | 6,293 | 49.66% | 0 | 0.00% | ||
Free Soil | John Parker Hale of New Hampshire | George Washington Julian of Indiana | 62 | 0.49% | 0 | 0.00% | ||
Total | 12,673 | 100.00% | 3 | 100.00% |
Results by county
editCounty | Franklin Pierce
Democratic |
Winfield Scott
Whig |
John Hale
Free Soil |
Margin | Total votes cast | ||||
# | % | # | % | # | % | # | % | ||
Kent | 1,422 | 47.20% | 1,591 | 52.80% | 0 | 0.00% | -169 | -5.61% | 3,013 |
New Castle | 3,038 | 51.77% | 2,768 | 47.17% | 62 | 1.06% | 270 | 4.60% | 5,868 |
Sussex | 1,858 | 49.00% | 1,934 | 51.00% | 0 | 0.00% | -76 | -2.00% | 3,792 |
Total: | 6,318 | 49.85% | 6,293 | 49.66% | 62 | 0.49% | 25 | 0.20% | 12,673 |
See also
editReferences
edit- ^ "1852 Presidential General Election Results - Delaware". U.S. Election Atlas. Retrieved March 17, 2015.
- ^ Burnham, Walter Dean (1955). Presidential ballots, 1836-1892. Internet Archive. Baltimore, Johns Hopkins Press. p. 320.