1868 United States presidential election in Maine
(Redirected from United States presidential election in Maine, 1868)
The 1868 United States presidential election in Maine took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for president and vice president.
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County Results
Grant 50–60% 60-70% 70-80%
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Maine voted for the Republican nominee, Ulysses S. Grant, over the Democratic nominee, Horatio Seymour. Grant won the state by a margin of 24.82%.
Results
edit1868 United States presidential election in Maine[1] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Republican | Ulysses S. Grant of Illinois | Schuyler Colfax of Indiana | 70,502 | 62.41% | 7 | 100.00% | ||
Democratic | Horatio Seymour of New York | Francis Preston Blair Jr. of Missouri | 42,460 | 37.59% | 0 | 0.00% | ||
Total | 112,962 | 100.00% | 7 | 100.00% |
See also
editReferences
edit- ^ "1868 Presidential General Election Results - Maine". U.S. Election Atlas. Retrieved March 17, 2015.