1868 United States presidential election in Massachusetts
(Redirected from United States presidential election in Massachusetts, 1868)
The 1868 United States presidential election in Massachusetts took place on November 3, 1868, as part of the 1868 United States presidential election. Voters chose 12 representatives, or electors to the Electoral College, who voted for president and vice president.
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Turnout | 66.9[1] 3.1 pp | |||||||||||||||||||||||||
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County Results
Grant 50–60% 60-70% 70-80% 80-90%
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Massachusetts voted for the Republican nominee, Ulysses S. Grant, over the Democratic nominee, Horatio Seymour. Grant won the state by a margin of 39.53%.
With 69.76% of the popular vote, Massachusetts would be Grant's second strongest victory in terms of popular vote percentage after neighboring Vermont.[2]
This is the last election in which Dorchester voted in a presidential election, as it was annexed by the city of Boston in 1869.
Results
edit1868 United States presidential election in Massachusetts[3] | ||||||||
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Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
Count | % | Count | % | |||||
Republican | Ulysses S. Grant of Illinois | Schuyler Colfax of Indiana | 136,379 | 69.76% | 12 | 100.00% | ||
Democratic | Horatio Seymour of New York | Francis Preston Blair Jr. of Missouri | 59,103 | 30.23% | 0 | 0.00% | ||
N/A | Others | Others | 26 | 0.01% | 0 | 0.00% | ||
Total | 195,508 | 100.00% | 12 | 100.00% |
See also
editReferences
edit- ^ Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
- ^ "1868 Presidential Election Statistics". Dave Leip’s Atlas of U.S. Presidential Elections. Retrieved March 5, 2018.
- ^ "1868 Presidential General Election Results - Massachusetts".