1876 United States presidential election in Massachusetts
(Redirected from United States presidential election in Massachusetts, 1876)
The 1876 United States presidential election in Massachusetts took place on November 7, 1876, as part of the 1876 United States presidential election. Voters chose 13 representatives, or electors to the Electoral College, who voted for president and vice president.
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| Turnout | 72.3%[1]  10.3 pp | |||||||||||||||||||||||||
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Massachusetts voted for the Republican nominee, Rutherford B. Hayes, over the Democratic nominee, Samuel J. Tilden. Hayes won the state by a margin of 15.90%.
Results
edit| 1876 United States presidential election in Massachusetts[2] | ||||||||
|---|---|---|---|---|---|---|---|---|
| Party | Candidate | Running mate | Popular vote | Electoral vote | ||||
| Count | % | Count | % | |||||
| Republican | Rutherford B. Hayes of Ohio | William A. Wheeler of New York | 150,064 | 57.80% | 13 | 100.00% | ||
| Democratic | Samuel J. Tilden of New York | Thomas A. Hendricks of Indiana | 108,777 | 41.90% | 0 | 0.00% | ||
| N/A | Others | Others | 779 | 0.30% | 0 | 0.00% | ||
| Total | 259,620 | 100.00% | 13 | 100.00% | ||||
See also
editReferences
edit- ^ Bicentennial Edition: Historical Statistics of the United States, Colonial Times to 1970, part 2, p. 1072.
- ^ "1876 Presidential General Election Results - Massachusetts".
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