1884 United States presidential election in Minnesota

Main article: 1884 United States presidential election

The 1884 United States presidential election in Minnesota took place on November 4, 1884, as part of the 1884 United States presidential election. Voters chose seven representatives, or electors to the Electoral College, who voted for president and vice president.

1884 United States presidential election in Minnesota

November 4, 1884

Nominee James G. Blaine Grover Cleveland Party Republican Democratic Home state Maine New York Running mate John A. Logan Thomas A. Hendricks Electoral vote 7 0 Popular vote 111,865 70,065 Percentage 58.78% 36.87%

County Results Blaine   50-60%   60-70%   70-80%   80-90%   90-100% Cleveland   40-50%   50-60%   60-70%   70-80%

President before election Chester A. Arthur Republican Elected President Grover Cleveland Democratic

Minnesota was won by Republican nominee, James G. Blaine, over the Democratic nominee, Grover Cleveland. Blaine won the state by a margin of 21.91%.

With 58.78% of the popular vote, Minnesota would prove to be Blaine's second strongest victory in terms of percentage in the popular vote after Vermont.

As of 2020, this remains the last time that a Republican presidential nominee would win a majority of the vote in Minnesota while losing nationally.

Results

1884 United States presidential election in Minnesota
Party		Candidate	Running mate	Popular vote		Electoral vote
				Count	%	Count	%
	Republican	James Gillespie Blaine of Maine	John Alexander Logan of Illinois	111,685	58.78%	7	100.00%
	Democratic	Grover Cleveland of New York	Thomas Andrews Hendricks of Indiana	70,065	36.87%	0	0.00%
	Prohibition	John Pierce St. John of Kansas	William Daniel of Maryland	4,684	2.47%	0	0.00%
	Greenback	Benjamin Franklin Butler of Massachusetts	Absolom Madden West of Mississippi	3,583	1.89%	0	0.00%
Total				190,017	100.00%	7	100.00%

See also

• United States presidential elections in Minnesota