1792 United States presidential election in Pennsylvania
The 1792 United States presidential election in Pennsylvania took place as part of the 1792 United States presidential election. Pennsylvania voters chose 15 members of the Electoral College,[1] each of whom, under the provisions of the Constitution prior to the passage of the Twelfth Amendment, cast two votes for President.
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Pennsylvania unanimously voted for nonpartisan candidate and incumbent President George Washington. The two best performing electors in Pennsylvania, Joseph Hiester and William Henry, were supported by both parties. They received 3,396 and 3,371 votes respectively. It is not known which one voted for Clinton.[2] The total for Washington only includes the 3,396 number as to not represent Pennsylvanian voters twice in popular vote figures.
Results
edit| 1792 United States presidential election in Pennsylvania | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Independent | George Washington | 3,396 | 100% | 15 | |
| Totals | 3,396 | 100% | 15 | ||
See also
editReferences
edit- ^ "1792 ELECTION FOR THE SECOND TERM, 1793-1797". National Archives. Retrieved August 4, 2012.
- ^ "A New Nation Votes". elections.lib.tufts.edu. Retrieved July 16, 2024.
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