1828 United States presidential election in Pennsylvania
(Redirected from United States presidential election in Pennsylvania, 1828)
The 1828 United States presidential election in Pennsylvania took place between October 31 and December 2, 1828, as part of the 1828 United States presidential election. Voters chose 28 representatives, or electors to the Electoral College, who voted for President and Vice President.
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County Results
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Pennsylvania voted for the Democratic candidate, Andrew Jackson, over the National Republican candidate, John Quincy Adams. Jackson won Pennsylvania by a margin of 33.32%.
To date, this is still the best Democratic Party performance in Pennsylvania in any federal election. It was also the last time to date Union County, Pennsylvania voted Democratic.
Results
edit1828 United States presidential election in Pennsylvania[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | Andrew Jackson | 101,652 | 66.66% | 28 | |
National Republican | John Quincy Adams (incumbent) | 50,848 | 33.34% | 0 | |
Totals | 152,500 | 100.0% | 28 |
References
edit- ^ "1828 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. Retrieved August 4, 2012.