1836 United States presidential election in Pennsylvania

Main article: 1836 United States presidential election

The 1836 United States presidential election in Pennsylvania took place between November 3 and December 7, 1836, as part of the 1836 United States presidential election. Voters chose 30 representatives, or electors to the Electoral College, who voted for President and Vice President.

1836 United States presidential election in Pennsylvania

November 3 – December 7, 1836

Nominee Martin Van Buren William Henry Harrison Party Democratic Whig Home state New York Ohio Running mate Richard Johnson Francis Granger Electoral vote 30 0 Popular vote 91,457 87,235 Percentage 51.18% 48.82%

County Results Van Buren   50-60%   60-70%   70-80%   80-90% Harrison   50-60%   60-70%   70–80%

President before election Andrew Jackson Democratic Elected President Martin Van Buren Democratic

Pennsylvania voted for the Democratic candidate, Martin Van Buren, over the Whig candidate, William Henry Harrison. Van Buren won Pennsylvania by a narrow margin of 2.36%. The result would ultimately prove decisive in Van Buren's victory; had Harrison won the state, then Van Buren would not have achieved a majority in the Electoral College, meaning that the election would have been decided in the House of Representatives.

Results

1836 United States presidential election in Pennsylvania
Party		Candidate	Votes	Percentage	Electoral votes
	Democratic	Martin Van Buren	91,457	51.18%	30
	Whig	William Henry Harrison	87,235	48.82%	0
Totals			178,692	100.0%	30

See also

• List of United States presidential elections in Pennsylvania