1844 United States presidential election in Pennsylvania
(Redirected from United States presidential election in Pennsylvania, 1844)
The 1844 United States presidential election in Pennsylvania took place between November 1 and December 4, 1844, as part of the 1844 United States presidential election. Voters chose 26 representatives, or electors to the Electoral College, who voted for President and Vice President.
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
County Results
| ||||||||||||||||||||||||||
|
Pennsylvania voted for the Democratic candidate, James K. Polk, over the Whig candidate, Henry Clay. Polk won Pennsylvania by a narrow margin of 1.91%.
Results
edit1844 United States presidential election in Pennsylvania[1] | |||||
---|---|---|---|---|---|
Party | Candidate | Votes | Percentage | Electoral votes | |
Democratic | James K. Polk | 167,447 | 50.50% | 26 | |
Whig | Henry Clay | 161,125 | 48.59% | 0 | |
Liberty | James G. Birney | 3,000 | 0.90% | 0 | |
Totals | 331,572 | 100.0% | 26 |
See also
editReferences
edit- ^ "1844 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. Retrieved August 4, 2012.