1864 United States presidential election in Pennsylvania
(Redirected from United States presidential election in Pennsylvania, 1864)
The 1864 United States presidential election in Pennsylvania took place on November 8, 1864, as part of the 1864 United States presidential election. Voters chose 26 representatives, or electors to the Electoral College, who voted for president and vice president.
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County Results
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Pennsylvania voted for the National Union candidate, incumbent Republican President Abraham Lincoln and his running mate Andrew Johnson. They defeated the Democratic candidate, George B. McClellan and his running mate George H. Pendleton. Lincoln won the state by a narrow margin of 3.5%.
Results
edit1864 United States presidential election in Pennsylvania[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
National Union | Abraham Lincoln (incumbent) | 296,391 | 51.75% | 26 | |
Democratic | George B. McClellan | 276,316 | 48.25% | 0 | |
Totals | 572,707 | 100.0% | 26 |
See also
editReferences
edit- ^ "1864 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. Retrieved August 3, 2012.