1872 United States presidential election in Pennsylvania
(Redirected from United States presidential election in Pennsylvania, 1872)
The 1872 United States presidential election in Pennsylvania took place on November 5, 1872, as part of the 1872 United States presidential election. Voters chose 29 representatives, or electors to the Electoral College, who voted for president and vice president.
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
County Results
| ||||||||||||||||||||||||||
|
Pennsylvania voted for the Republican candidate, Ulysses S. Grant, over the Liberal Republican candidate, Horace Greeley. Grant won Pennsylvania by a margin of 24.42%.
Results
edit1872 United States presidential election in Pennsylvania[1] | |||||
---|---|---|---|---|---|
Party | Candidate | Votes | Percentage | Electoral votes | |
Republican | Ulysses S. Grant (incumbent) | 349,589 | 62.07% | 29 | |
Liberal Republican | Horace Greeley | 212,041 | 37.65% | 0 | |
Prohibition | James Black | 1,632 | 0.29% | 0 | |
Totals | 563,262 | 100.0% | 29 |
See also
editReferences
edit- ^ "1872 Presidential General Election Results - Pennsylvania". U.S. Election Atlas. Retrieved August 3, 2012.