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Please note that it is usually a bad idea to restore material that has been reverted without first discussing the matter and coming to a consensus. See Wikipedia:BOLD, revert, discuss cycle for an explanation of a widely accepted way of proceeding in such cases. SpinningSpark 14:53, 18 June 2017 (UTC)Reply

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Transmission Lines at DC

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The trick is to use the full expression for Z, Vprop, α and β.

Z=sqrt{ (R+ωL) / (G+ωC) = sqrt {R/G} when ω=0. For the moment, consider that G (shunt conductance) is very small, but not zero. We see that the characteristic impedance at DC approaches a very large number, hence, for a fixed voltage, current is very small at DC. This characteristic impedance is so large that the magnitude of the reflection coefficient at both the load and source is close to unity. In other words, there is both a forward traveling wave and a reverse wave. You have to sort the voltage and current at each point into forward and backward components. Once you have done that, the ratio of the forward wave voltage to forward wave current is Z and the ratio of the reverse voltage and current is Z.

Even if the load is a perfect open, there will be current in the line due to current leaking across the non-zero shunt conductance, G.

If G is actually zero at DC, then you have to take some limits to avoid dividing by 0. If you do it correctly, you will see that the limits produce the usual DC results. Constant314 (talk) 12:56, 22 January 2018 (UTC)Reply

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