This article relies largely or entirely on a single source. (July 2024) |
The 1792 United States presidential election in Rhode Island took place as part of the 1792 United States presidential election. Voters chose 4 representatives, or electors to the Electoral College who voted for President and Vice President.
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Rhode Island unanimously voted for the incumbent Independent President George Washington.
Results
edit1792 United States presidential election in Rhode Island[1] | |||||
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Party | Candidate | Votes | Percentage | Electoral votes | |
Independent | George Washington (incumbent) | — | — | 4 | |
Federalist | John Adams | — | — | 4 | |
Totals | — | — | 8 |
See also
editReferences
edit- ^ "A New Nation Votes". elections.lib.tufts.edu. Retrieved 2024-07-19.