The 1796 United States presidential election in Kentucky took place between 4 November and 7 December 1796, as part of the 1796 United States presidential election. The voters chose four representatives, or electors to the Electoral College, who voted for President and Vice President.
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Kentucky cast four electoral votes for the Democratic-Republican candidate Thomas Jefferson over the Federalist candidate and incumbent Vice President John Adams. The electoral votes for Vice president were cast for Jefferson's running mate Aaron Burr from New York. The state was divided into four electoral districts with one elector each, whereupon each district's voters chose the electors.[1]
Results
edit| 1796 United States presidential election in Kentucky[2] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Democratic-Republican | Thomas Jefferson | — | 100.00% | 4 | |
| Federalist | John Adams | — | 0.00% | 0 | |
| Totals | — | 100.00% | 4 | ||
See also
editReferences
edit- ^ "1796 Presidential General Election Results". U.S. Election Atlas. Retrieved 14 July 2023.
- ^ "1796 Presidential Election". 270towin.com. Retrieved 14 July 2023.