The 1796 United States presidential election in New Hampshire took place between November 4 to December 7, 1796, as part of the 1796 United States presidential election to elect the President. Voters chose five representatives, or electors to the Electoral College, who voted for President and Vice President.
 | ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
| ||||||||||||||||||||||||||
New Hampshire voted for Federalist candidate and Vice President John Adams, over the Democratic-Republican candidate and Secretary of State Thomas Jefferson by a total of 78.6% margin of the popular vote, making this the largest margin for a presidential candidate in the state of New Hampshire.
Results
edit| 1796 United States presidential election in New Hampshire[1] | |||||
|---|---|---|---|---|---|
| Party | Candidate | Votes | Percentage | Electoral votes | |
| Federalist | John Adams | 3,265 | 89.3% | 6 | |
| Democratic-Republican | Thomas Jefferson | 393 | 10.7% | ||
| Totals | 3,658 | 100.0% | 6 | ||
See also
editReferences
edit- ^ a b "Presidential Results: National, 1796". votearchive.com. Retrieved 2024-06-20.