1798 Delaware gubernatorial election

The 1798 Delaware gubernatorial election was held on October 2, 1798.

1798 Delaware gubernatorial election

← 1795 October 2, 1798 1801 →
 
Nominee Richard Bassett David Hall
Party Federalist Democratic-Republican
Popular vote 2,490 2,068
Percentage 52.50% 43.60%

Bassett:      50–60%

Governor before election

Daniel Rogers (acting)
Federalist

Elected Governor

Richard Bassett
Federalist

Acting Governor Daniel Rogers was not eligible for re-election under the Delaware Constitution of 1792.

Federalist nominee Richard Bassett defeated Democratic-Republican nominee David Hall and Federalist nominee Barclay Townsend with 52.50% of the vote.

General election

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Results

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1798 Delaware gubernatorial election[1][2][3][4]
Party Candidate Votes % ±%
Federalist Richard Bassett 2,490 52.5%
Democratic-Republican David Hall 2,068 43.6%
Federalist Barclay Townsend 185 3.90%
Majority 422 8.90%
Turnout 4,743 100.00%
Federalist hold Swing

References

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  1. ^ "DE Governor, 1798". Our Campaigns. Retrieved December 8, 2020.
  2. ^ Congressional Quarterly 1998, p. 46.
  3. ^ Glashan 1979, pp. 50–51.
  4. ^ Dubin 2003, p. 26.

Bibliography

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  • Gubernatorial Elections, 1787-1997. Washington, D.C.: Congressional Quarterly Inc. 1998. ISBN 1-56802-396-0.
  • Glashan, Roy R. (1979). American Governors and Gubernatorial Elections, 1775-1978. Meckler Books. ISBN 0-930466-17-9.
  • Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson, North Carolina: McFarland. ISBN 978-0-7864-1439-0.