1804 United States presidential election in Ohio

The 1804 United States presidential election in Ohio took place as part of the 1804 United States presidential election. Voters chose three representatives, or electors, to vote for president and vice president. It was the first time that Ohio took part in United States presidential election.

1804 United States presidential election in Ohio

1808 →
 
Nominee Thomas Jefferson Charles C. Pinckney
Party Democratic-Republican Federalist
Home state Virginia South Carolina
Running mate George Clinton Rufus King
Electoral vote 3 0
Popular vote 2,593 364
Percentage 87.69% 12.31%

President before election

Thomas Jefferson
Democratic-Republican

Elected President

Thomas Jefferson
Democratic-Republican

Results

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1804 United States presidential election in Ohio[1]
Party Candidate Votes Percentage Electoral votes
Democratic-Republican Thomas Jefferson (incumbent) 2,593 87.69% 3
Federalist Charles Cotesworth Pinckney 364 12.31% 0
Totals 2,957 100.0% 3

References

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  1. ^ "A New Nation Votes". elections.lib.tufts.edu. Retrieved July 3, 2023.