1806 Virginia gubernatorial election

The 1806 Virginia gubernatorial election was held on 30 November 1806 in order to elect the Governor of Virginia. Incumbent Democratic-Republican Governor of Virginia William H. Cabell won re-election in the Virginia General Assembly as he ran unopposed.[1][2][3]

1806 Virginia gubernatorial election

← 1805 30 November 1806 1807 →
 
Nominee William H. Cabell
Party Democratic-Republican
Popular vote 1
Percentage 100.00%

Governor before election

William H. Cabell
Democratic-Republican

Elected Governor

William H. Cabell
Democratic-Republican

General election

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On election day, 30 November 1806, Democratic-Republican nominee William H. Cabell easily won re-election as he ran unopposed. Cabell was sworn in for his second term on 1 December 1806.[4][5]

Results

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Virginia gubernatorial election, 1806[6][7]
Party Candidate Votes %
Democratic-Republican William H. Cabell (incumbent) 1 100.00
Total votes 1 100.00
Democratic-Republican hold

References

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  1. ^ "Gov. William Henry Cabell". nga.org. January 13, 2018. Retrieved May 19, 2023.
  2. ^ "General Assembly of Virginia". The enquirer. Richmond, VA. December 5, 1806. p. 2. Retrieved May 19, 2023.
  3. ^ "Washington City. Wednesday, December 10". The national intelligencer and Washington advertiser. Washington, D.C. December 10, 1806. p. 3. Retrieved May 19, 2023.
  4. ^ "VA Governor". ourcampaigns.com. February 10, 2013. Retrieved May 19, 2023.
  5. ^ "Virginia Legislature. House of Delegates. Wednesday, December 3, 1806". Virginia Argus. Richmond, VA. December 5, 1806. p. 2. Retrieved May 19, 2023.
  6. ^ Dubin, Michael J. (2003). United States Gubernatorial Elections, 1776-1860: The Official Results by State and County. Jefferson: McFarland & Company. ISBN 9780786414390.
  7. ^ "Virginia 1806 Governor". elections.lib.tufts.edu. December 5, 1806. Retrieved May 19, 2023.